Coordinates to world map location [Complete/Full Source]

[toenailed]

Well the world map, excluding the area with walls, is 64x64 slots. We're trying to edit the individual slot you're standing on, not the entire acre (16x16).

no .. i mean .. the world map has 16 tiles with each tiles has 16 x 16 slot .. so it is

(16 * 16) * 16
256 * 16
4096 and since map is a perfect square that would makes it 64x64

but in RAM it was distributed by tile and not by 64x64 .. so meaning row 1 to 16 and column 1 to 16 or TIle 1 uses the addresses 0x21E3124 to 0x21E3322 while row 1 to 16 and column 17 to 32 or the Tile 2 use the addresses 0x21E3324 to 0x21E3522 .. so meaning tile 6 or row 17 to 32 and column 17 to 32 is using 0x21E3b24 to 0x21E3d22

and then above situation where it is in row 64 and column 2 meaning it was under the tile 13

http://toenailed.game-hackers.com/images/tile13.PNG

anyway my solution .. is to calculate where tile you are and calculate on what slot you are on that tile .. ill post it later .. i just need to shorten it a bit ..

[Maniac]

Nice job toe, mind sending me the source when your done?

[Vash]

Ah yes, I understand. The addresses don't go in order properly. Well I hope you get it working. It will be one epic code haha.

[Charlie]

"Amateur Coding"
As soon as people see this post, they will say, " ! This is Amateur coding!?" and run away.
:lol:

[Maniac]

lol... I was thinking the same thing..

[toenailed]

anyway im still lazy so ill just give the idea

[TileNo] = ((((([rowSlot]+16)-1)/16)-1)*4) + ((([columnSlot]+16)-1)/16)

[TileNo] = (((((64+16)-1)/16)-1)*4) + (((2+16)-1)/16)
[TileNo] = (((((80)-1)/16)-1)*4) + (((18)-1)/16)
[TileNo] = (((79/16)-1)*4) + (17/16)
[TileNo] = ((4-1)*4) + 1
[TileNo] = (3*4) + 1
[TileNo] = 12 + 1
[TileNo] = 13

[SlotNo] = ((([rowSlot] - ((([rowSlot]-1)/16)*16))-1)*16) + ([columnSlot] - ((([columnSlot]-1)/16)*16))

[SlotNo] = (((64 - ((64-1/16)*16))-1)*16) + ((2 - (((2-1)/16)*16))
[SlotNo] = (((64 - ((63/16)*16))-1)*16) + (2 - ((1/16)*16))
[SlotNo] = (((64 - ((3)*16))-1)*16) + (2 - (0*16))
[SlotNo] = (((64 - 48)-1)*16) + (2 - 0)
[SlotNo] = (((16-1)*16) + 2
[SlotNo] = ((15 * 16) + 2
[SlotNo] = ((15 * 16) + 2
[SlotNo] = 240 + 2
[SlotNo] = 242

[FinalAddress] = ((([TileNo]-1) * 256) + ([SlotNo]-1))*2) + 0x021E3124

[FinalAddress] = (((13-1) * 256) + (242-1)*2) + 0x021E3124
[FinalAddress] = ((12 * 256) + 241)*2) + 0x021E3124
[FinalAddress] = (3072 + 241)*2) + 0x021E3124
[FinalAddress] = (3313*2) + 0x021E3124
[FinalAddress] = 0x19E2 + 0x021E3124
[FinalAddress] = 0x21E4B06

obviously in asm it can be shorten a polish a bit .. but still as i imagine this .. final code would be as long as my LOZ Dpad

PS. all remainder is ignored

for division in ARM ASM use this routine

mov r0,#0
mov r1,#0x3E   @---dividend
mov r2,#0xF     @---divisor

div:
cmp r1,r2
addge r0,#1
subge r1,r2
bge div

after the routine r0 = has the qoutient & r1 = has the remainder/Modulus

[Vash]

Wow. All I can say is wow. That is one advanced formula right there. I don't even want to ask how you came up with it. Excellent work! I can't wait for the final code...

EDIT: I guess I'll give it a shot, since I just got your direct quote saying you would hope I could do it I'll give it a go. heheh

[toenailed]

this is the continuation of the recent code we are using .. obviously this is just a sample and very badly coded .. it might have error and obviously it can be shorten .. i just try to make it understandable to every one and hope even for the newbie ..

since r0 = rowSlot and r1 = columnSlot from viewtopic.php?p=3421#p3421

@((((([rowSlot]+16)-1)/16)-1)*4) + ((([columnSlot]+16)-1)/16)
@[TileNo] r2 will have the [TileNo]
add r8,r0, #16
bl checke
sub r6,#1
mov r2,r6, lsl #2
add r8,r1, #16
bl checke
add r2,r6

@((([rowSlot] - ((([rowSlot]-1)/16)*16))-1)*16) + ([columnSlot] - ((([columnSlot]-1)/16)*16))
@[SlotNo] r3 will have the [SlotNo]
mov r8,r0
bl checke
mov r3,#16
mul r4,r3,r6
sub r4,#1
mul r4,r3
sub r4,r0
mov r8,r1
bl checke
mul r3,r6
sub r3,r1
add r3,r4

@FInalAddress r0 will have the Final Address
@((([TileNo]-1) * 256) + ([SlotNo]-1))*2) + 0x021E3124
sub r3, #1 
lsl r3, #8
sub r4,#1
lsl r4, #1
add r4,r3
ldr r1, =0x021E3124
add r4,r1

Here is the last macro and must be added on the last part of the wholecode

checke:
sub r8, #1
mov r6,#0
div:
cmp r8,#16
addge r6,#1
subge r8,#16
bge div
bx lr

r4 will contain the Final Address

[Vash]

Interesting. Since r4 receives the final address, can you make it write that address to 0x02000000? I just want to see if it's working properly.

EDIT:

I just changed this section to:

@FInalAddress r0 will have the Final Address
@((([TileNo]-1) * 256) + ([SlotNo]-1))*2) + 0x021E3124
sub r3, #1 
lsl r3, #8
sub r4,#1
lsl r4, #1
add r4,r3
ldr r1, =0x021E3124
add r4,r1
ldr r5, =0x02000000
str r4,[r5]

Wouldn't that put the final address at 0x02000000?

[Maniac]

Yes vash, from looking at it quickly it would.. but why even bother putting it to 0x02000000 when you can do the rest in ASM?